Integrate Hard Integral Homework Problem: Step by Step Guide

[evol_w10lv]

Homework Statement

How to integrate:

Homework Equations

The Attempt at a Solution

I used formula: sin^2(t) = ( 1-cos^2(t))
and now it's:

Then:
u=cos(t)
du=-sin(t)

What to do next?

 

[arildno]

We may now rewrite the integrand as:
-6\sqrt{s^{2}+1}, s=\frac{\sqrt{5}u}{2}
Now, utilize the trigonometric identity:
\tan^{2}(y)+1=\frac{1}{\cos^{2}(y)}
in a creative way.

 

[CAF123]

Where did the 3 come from?
Try using the identity 1 + tan²x = sec²x after some initial manipulation of the integrand.

 

[evol_w10lv]

Actually the task sounds like this:

Maybe I have to use polar coordinates? Any sugestions? Before I tried with diferent way, but I guess that integration without polar coordinates is too hard.

 

[arildno]

L is a segment of an ellipse. You might go polar, but you can eliminate t as well, and express y as a function of x(Hint: sin^+cos^2=1)

 

[evol_w10lv]

Seems to me that variant when we use y=y(x) is more complicated than variant with polar coordinates.

We may now rewrite the integrand as:
-6\sqrt{s^{2}+1}, s=\frac{\sqrt{5}u}{2}
Now, utilize the trigonometric identity:
\tan^{2}(y)+1=\frac{1}{\cos^{2}(y)}
in a creative way.

Not clear, how did you get there: s=\frac{\sqrt{5}u}{2}
We didn't learn about triple substitution, but I want to understand, how to get the final result. Can you explain some how?