Integrate x^2 /square root (x^2 +1)

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Homework Help Overview

The problem involves integrating the function x^2 divided by the square root of (x^2 + 1). Participants are exploring various approaches to simplify their results and clarify their understanding of hyperbolic functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different methods for integration, including substitution techniques and the relationship between hyperbolic functions. Questions arise about simplifying expressions involving cosh(arcsinh x) and whether certain substitutions would yield a simpler result.

Discussion Status

The discussion is active, with participants sharing insights and alternative methods. Some guidance has been offered regarding the simplification of hyperbolic functions, and there is a recognition of the potential for easier substitution methods. However, no consensus has been reached on a single approach.

Contextual Notes

Participants are working within the constraints of homework guidelines, which may limit the use of certain methods or require specific forms for answers. There is also a focus on ensuring that results are expressed in algebraic terms rather than leaving them in hyperbolic function forms.

yanjt
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Hi,
the question is integrate x^2 /square root (x^2 +1).

I tried to do it but i was stucked in the very last step.at the end,I got x/2 * cosh(arcsinh x) + 1/2 * arcsinh x - arcsin (square root (x^2 + 1)) +C. I dunnoe how can I simplify cosh(arcsinh x) into simplier form in term of x. I hope what I wrote is not too confusing.Thanks!
 
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I haven't checked your integration but arcsinh(z)=ln(z+sqrt(1+z^2)). You can put that into cosh(y)=(e^y+e^(-y))/2 and get an algebraic form for cosh(arcsinh(z)).
 
Hi yanjt! :smile:

(have a square-root: √ and try using the X2 tag just above the Reply box :wink:)

i] cosh(arcsinh x) is cosh of the "angle" whose sinh is x … so just use cosh2 - sinh2 = 1. :wink:

ii] why is your result so complicated? just use a substitution. :smile:
 


Thanks, dick n tiny-tim!:smile:

I did it in this way:

x2/√(x2+1) = √(x2+1) - 1/√(x2+1)

Integrate 1/√(x2+1) = arcsinh x
For √(x2+1),i subsitute x=sinh t.
So, integrate √(x2+1 = cosh2t dt
= 1/4 sinh 2t + t/2
=1/4 (2 sinh t cosh t) + arcsinh x/2
=x/2 (cosh(arcsinh x)) + arcsinh x/2
 
Hi yanjt! :smile:

Wouldn't it have been easier to substitute x = sinht at the very start? :wink:

(and you can't leave cosh(arcsinh x) as it is … you must convert that into something more "algebraic" :smile:)
 


ooohhhh yeah!y i didnt think of tat?:confused: tat's a faster n easier way to do it!thanks!:smile: but is integrate 1/cosh x = 1/sinh x?can i jus integrate like tat?

i know tat i can't jus leave cosh(arcsinh x) as my final answer.tat's y i m stucked in this step. but i will try to change it into somethg more "algebraic" using the methods tat dick n u mentioned in the first 2 posts.
 

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