Integrating 1/2x: Comparing Methods and Solutions

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The discussion centers on integrating the function ∫(1/2x)dx, where two methods yield seemingly different results. The first method factors out (1/2), leading to (1/2)ln|x| + C. The second method involves a substitution u = 2x, resulting in (1/2)ln|2x| + C. Despite the different forms, both answers are valid due to the properties of logarithms, as ln(2x) can be expressed as ln(x) + ln(2). Thus, both integration methods are correct and yield equivalent results when considering the constant of integration.
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Homework Statement



∫(1/2x)dx

The Attempt at a Solution



I factor out (1/2) and i get ∫(1/2x)dx=(1/2)ln|x|+C
∫(1/2x)dx
(1/2)∫(1/x)dx
(1/2)ln|x|+C

But can't i say that u=2x and dx=du/2 and get ∫(1/2x)dx= (1/2)ln|2x| + C
∫(1/2x)dx
u=2x
∫(1/u)(du/2)
∫(1/2u)du
(1/2)∫(1/u)dx
(1/2)ln|u| + C
(1/2)ln|2x| + C

if i can do this, i get two different answers...

can i use the last method?
 
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ln 2x = ln x + ln 2. One of your C constants is equal to the other plus ln 2.

Both your answers are right...
 
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