Integrating e^x(cosx) | Step-by-Step Solution for Homework

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Homework Help Overview

The discussion revolves around the integration of the function e^x(cos x), with participants exploring various approaches and interpretations of the integration process. The original poster expresses confusion regarding their attempts and the resulting equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the steps involved in integrating e^x(cos x), with some questioning the validity of their manipulations and the resulting equations. There is a focus on understanding the relationships between different forms of the integral presented.

Discussion Status

The conversation is ongoing, with participants providing insights and clarifications about the integration process. Some have suggested alternative methods, such as using Euler's formula, while others are still grappling with the implications of their derived equations.

Contextual Notes

There appears to be some confusion regarding the steps taken in the integration process, particularly about the equivalence of certain expressions. Participants are also navigating the implications of their findings within the constraints of their homework assignment.

theBEAST
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Homework Statement


I attached a picture of my attempt, it seems to loop back... Maybe I made a mistake... If not how am I suppose to integrate this? Thank you!
 

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Stop at the third line. Now move the integral of cos(x)*e^x on the right to the left. Then you are basically done. The third line gives you an equation where the only integral is cos(x)*e^x. Solve for it.
 
Dick said:
Stop at the third line. Now move the integral of cos(x)*e^x on the right to the left. Then you are basically done. The third line gives you an equation where the only integral is cos(x)*e^x. Solve for it.

Oh I see, I got

∫(e^xcosx dx)=(e^xsinx+e^xcosx)/2

But how did I get :
∫(e^xcosx dx)=e^xsinx+e^xcosx-∫(e^xcosx dx) (in the third step)

and

∫(e^xcosx dx)=∫(e^xcosx dx) (in the last step)

The two are not the same thing?
 
theBEAST said:
Oh I see, I got

∫(e^xcosx dx)=(e^xsinx+e^xcosx)/2

But how did I get :
∫(e^xcosx dx)=e^xsinx+e^xcosx-∫(e^xcosx dx) (in the third step)

and

∫(e^xcosx dx)=∫(e^xcosx dx) (in the last step)

The two are not the same thing?

Both of those statements are true. The first one tells you something useful. The second one is also true. But it doesn't tell you anything useful. They don't conflict with each other.
 
Last edited:
there is a really slick way to do this with Eulers formula. using e^(ix)=isin(x)+cos(x)
By substituting e^(ix) in and then taking the real part at the end.
 

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