- #1
musichael
- 10
- 0
I can't figure out how to this integral. I keep coming up with the wrong answer. Can someone please show me a detailed solution?
musichael said:ok first i did ln(14-.0003x^2) divided by the derivative of the inside. but when i plug in the definate integral values i can't get the correct answer.
musichael said:I tried using partial fractions but I can't figure out how to factor the bottom expression
Integrating from 0 to 200 means finding the area under the curve of a given function from x=0 to x=200.
The function 1/(14-(.0003x^2)) represents the height of the curve at any given x-value. It is the integrand that is being integrated to find the area under the curve.
The limits of integration, in this case 0 and 200, determine the range of x-values for which the area under the curve is being calculated. Other integrations may have different limits that correspond to different ranges of x-values.
Yes, there are various methods for integrating from 0 to 200, such as the midpoint rule, trapezoidal rule, and Simpson's rule. The choice of method depends on the complexity of the function and the desired level of accuracy.
The result of this integration represents the total area under the curve of the given function from x=0 to x=200. In other words, it gives the value of the definite integral of the function over the given interval.