Integrating $\int_{C}F\cdot dr$ with F and r Given

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Homework Help Overview

The problem involves computing the line integral of a vector field along a specified curve. The vector field is given as F = and the curve is parameterized by r = for 0 ≤ t ≤ 1.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the challenges of integrating the resulting expression after substitution into the integral. There is mention of using Green's theorem, but it is noted that the problem is not two-dimensional. Some participants explore the possibility of finding a potential function to facilitate the integration.

Discussion Status

The discussion includes attempts to evaluate the integral, with some participants expressing uncertainty about specific terms. There is a suggestion that finding a potential function could aid in the integration process. Multiple interpretations of the integral's solvability are being explored, and some participants have shared their results, although there is no consensus on the final answer.

Contextual Notes

Participants are working under the constraints of the problem statement and are questioning the applicability of certain mathematical techniques, such as Green's theorem, in this context. There is also mention of the clarity of shared work, indicating that visual representation may be a factor in understanding the solutions presented.

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Homework Statement


The problem says to compute the following integral.

[tex]\int_{C}F\cdot dr[/tex]
Where
[tex]F=<e^y,xe^y,(z+1)e^z> \ \ and \ \ r=<t,t^2,t^3>,0\leq t \leq 1[/tex]

2. The attempt at a solution
Basically when I plug everything in, I get an integral that CANT be solved. At first I thought to use Greens theorem, but I can't because it isn't two dimensional. When I plug everything in, I get..

[tex]\int^{1}_{0} (2t^2+1)e^{t^2}+3t^5e^{t^3}+3t^2e^{t^3}dt[/tex]

The only one I can immediate see is possible to do is the last term. MAYBE the second one, but definitely not the first one. (Not one part of it anyway.)

The first part of the question asked to find to potential function and I did that, I don't know if that would be in anyway relevant to this though.

Thanks!
 
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That's a good one! Had me scratching my head for a while. If you can get a potential function then you KNOW you can integrate it by using that. So no, you can't do e^(t^2) and you can't do t^2*e^(t^2). But you CAN do (2t^2+1)*e^(t^2). Wanna try and figure it out before I tell you??
 
Ohh! Thats interesting! Yes let me do it now. :)
 
Okay I got an answer of 3e. Here is my work.

http://img203.imageshack.us/img203/2750/photo1piq.jpg

Thanks a lot! :D!
 
Last edited by a moderator:
Xyius said:
Okay I got an answer of 3e. Here is my work.

http://img203.imageshack.us/img203/2750/photo1piq.jpg

Thanks a lot! :D!

That's a little hard to read. But I get 2e.
 
Last edited by a moderator:
Yeah sorry the resolution isn't too great. Anyway, I will post my work in detail later using Latex.
 
Xyius said:
Yeah sorry the resolution isn't too great. Anyway, I will post my work in detail later using Latex.

You can check your answer using the potential expression, right? What does that say?
 

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