Integrating tan^3 x: Tips and Tricks for Solving ∫tan3x dx

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SUMMARY

The forum discussion focuses on solving the integral ∫tan³(x) dx using various integration techniques. Participants clarify that ∫tan³(x) dx is not equal to ∫tan(x) dx + ∫tan²(x) dx, emphasizing the need for proper substitution and integration methods. The correct approach involves using the identity sec²(x) - tan²(x) = 1 and applying u-substitution with u = sec(x) to simplify the integral. The final expression for the integral is derived as (sec(x))²/2 + ln(|cos(x)|) + C.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sec²(x) - tan²(x) = 1.
  • Familiarity with u-substitution in integration.
  • Knowledge of basic integration rules, including ∫(1/x) dx = ln|x| + C.
  • Ability to manipulate and simplify trigonometric functions during integration.
NEXT STEPS
  • Study advanced integration techniques, including integration by parts.
  • Learn more about trigonometric integrals and their properties.
  • Explore the application of u-substitution in various integral forms.
  • Practice solving integrals involving higher powers of trigonometric functions.
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Students studying calculus, mathematics educators, and anyone looking to improve their skills in solving trigonometric integrals.

  • #31
Zondrina said:
No that looks fine. Except you have another ##u## sitting around that you need to sub back in for. You can also combine both constant terms into one constant term. Call it ##C##.

Yes it is also a rule that ##\int \frac{1}{x} dx = ln|x|##.

##\int \frac{1}{x^n} =##

##\frac{x^{n+1}}{n+1}## if ##n ≠ 1##

##ln|x|## if ##n = 1##


So then
= u2/2 + C + ∫ du/u
= u2/2 + ln (|u|) + C
= u2/2 + ln (|cos x|) + C?
= (sec x)2/2 + ln (|cos x|) + C?
 
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  • #32
missn525 said:
So then
= u2/2 + C + ∫ du/u
= u2/2 + ln (|u|) + C
= u2/2 + ln (|cos x|) + C?
= (sec x)2/2 + ln (|cos x|) + C?

Yes that looks good now.
 
  • #33
Zondrina said:
Yes that looks good now.

Is there anything left?
 
  • #34
Thanks for all the help!
 
Last edited:

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