Integrating tan^5(6x) sec^3(6x) - A Guide

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SUMMARY

The integral of tan^5(6x) sec^3(6x) can be simplified by using the substitution u = 6x, leading to the expression (1/6) ∫ tan^5(u) sec^3(u) du. By applying trigonometric identities, the integral transforms into ∫ (sec^9(u) - 3sec^7(u) + 3sec^5(u) - sec^3(u)) du. The discussion emphasizes the importance of careful substitutions and the use of identities to facilitate the integration process.

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Homework Statement


\int tan^5(6x) sec^3(6x) dx



Homework Equations





The Attempt at a Solution


first off I set u=6x to get 1/6\int tan^5(u) sec^3(u) dx
then I used trig identities to put tangent in terms of secant and I came up with

\int sec^9(u)-3sec^7(u)+3sec^5(u)-sec^3(u) dx
Not sure where to go from here, or if I'm doing this the right way
 
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Watch your substitutions.

\frac 1 6\int\tan^{5}u\sec^{3}udu

\frac 1 6\int\tan^{4}u\sec^{2}\sec u\tan udu

*\tan^{2}u+1=\sec^{2}u

Take it from here.
 

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