Integrating x^3/(1+x^2) from 0 to 1.48766439

[Swerting]

Homework Statement

I have to take an integral of $$x^3/(1+x^2)$$ from zero to 1.48766439...(I have the number).

Homework Equations

None really.

The Attempt at a Solution

Well, I tried and tried, and I could not find a single way to separate the top from the bottom. Also, I tried u substitution of both $$x^3$$ and $$1+x^2$$ but it never seemed to work out. I'm not sure if this would be good for integration of parts, since I believe that one must be able to be integrated multiple times, such as $$e^x$$, so any nudge in the right direction would help. I have the correct answer, I just would like to be able to know how to get to it. Thank you for your time.

-Swerting

 

[Dick]

Try writing it as x^2*x/(1+x^2). Now substitute u=1+x^2. Replace the x^2 in the numerator by u-1. Do you see it now?

 

[Swerting]

Ah yes! I completely forgot about that! Thank you very much, I do believe I have it now!