Integration: Evaluate the Definite Integral?

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SUMMARY

The discussion focuses on evaluating the definite integral ∫ (x^3) / (1 + x^4) dx from 0 to 1. The user correctly identifies the substitution method with u = 1 + x^4, leading to du = 4x^3 dx. After substituting, the integral simplifies to (1/4) ∫ u^-1 du, which evaluates to (1/4) ln(2). The user initially expresses uncertainty about the steps but ultimately confirms their understanding of the solution.

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KAISER91
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Homework Statement



Q) Evaluate The Definite Integral:

∫ (x^3) / (1 + x^4) dx

Upper Limit: 1
Lower Limit: 0


Homework Equations





The Attempt at a Solution



I think I'm on the right track;


u = 1 + x^4
du/dx = 4x^3
du = 4x^3 dx
1/4 du = x^3 dx


When x = 0 ; u = 1
When x = 1 ; u = 2


Therefore;

∫ (1/4 du) / u

1/4 ∫ u^-1




I'm not sure if that last step is correct; but here is where I get stuck.

Help will be appreciated. Thanks.



BTW;

Answer given is (1/4) ln 2
 
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[tex] \int \frac{dx}{x} = ln(x) + C[/tex]
 
LMAOO!

Silly me.

Nevermind, I got it now.
 

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