Integration Help: Solve ∫sqrt(a^2-x^2)/x*sqrt(x^2-b^2)

  • Thread starter Thread starter WiFO215
  • Start date Start date
  • Tags Tags
    Integration
Click For Summary
SUMMARY

The integral ∫sqrt(a²-x²)/(x*sqrt(x²-b²)) cannot be solved using standard methods, as confirmed by Mathematica. The discussion highlights the challenges faced when attempting various substitutions, including the transformation u = x² - b². The participants noted that the expression (a² - x²)/(x² - b²) simplifies to (b² - a²)/(x² - b²) - 1, but this did not lead to a viable solution. Overall, the integral remains unsolvable with the techniques discussed.

PREREQUISITES
  • Understanding of integral calculus, specifically techniques for solving definite and indefinite integrals.
  • Familiarity with substitution methods in integration.
  • Knowledge of algebraic manipulation involving square roots and rational expressions.
  • Experience with computational tools like Mathematica for verifying integral solutions.
NEXT STEPS
  • Research advanced integration techniques, including trigonometric and hyperbolic substitutions.
  • Explore the use of Mathematica for symbolic computation and integral evaluation.
  • Study the properties of integrals involving square roots and rational functions.
  • Investigate the implications of integrals that cannot be expressed in terms of elementary functions.
USEFUL FOR

Students and educators in calculus, mathematicians dealing with complex integrals, and anyone interested in advanced integration techniques and computational verification methods.

WiFO215
Messages
416
Reaction score
1

Homework Statement



\int \sqrt{a^{2}-x^{2}}/x*\sqrt{x^{2}-b^{2}}



The Attempt at a Solution



I tried all sorts of substitutions and none work. Please help me.
 
Last edited:
Physics news on Phys.org
Would it help to know that
\frac{a^2- x^2}{x^2- b^2}= \frac{b^2- a^2}{x^2- b^2}- 1
 
Edit notice: I multiplied the integrand by 1/x. Its not to the xth root of. I didn't type that in first type.
 
I don't have a clue how that helps HallsofIvy.
 
Mathematica says this rubbish can't be solved.
 
Have you editted the first post? I didn't notice that "x" outside the square root before.
Let u= x2- b2 so that du= 2xdx
\sqrt{\frac{b^2-a^2}{x^2- b^2}-1}= \sqrt{\frac{A}{u}- 1}
 
Yes. I edited the first post. Forget it though. I think what I did is wrong anyway.
 

Similar threads

  • · Replies 105 ·
4
Replies
105
Views
7K
Replies
9
Views
3K
  • · Replies 22 ·
Replies
22
Views
3K
Replies
20
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
6K