Integration of Exponential Function with Limits from 0 to t

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SUMMARY

The discussion centers on the integration of the function F(t) = 1 - exp(-∫(1/(t+2)) dt) with limits from 0 to t. The initial solution presented incorrectly interprets the integral and contains algebraic mistakes, leading to an erroneous final expression of F(t) = 2t - 3. A critical review highlights the need for clarity in the exponential function's formulation and proper handling of logarithmic properties during simplification.

PREREQUISITES
  • Understanding of integral calculus, specifically integration techniques involving exponential functions.
  • Familiarity with logarithmic identities and properties.
  • Knowledge of limits in calculus and their application in definite integrals.
  • Ability to manipulate algebraic expressions accurately.
NEXT STEPS
  • Review integration techniques for exponential functions, focusing on the integral of 1/(t+2).
  • Study the properties of logarithms and their application in calculus problems.
  • Practice solving definite integrals with limits to reinforce understanding of the concept.
  • Explore common pitfalls in algebraic manipulation to avoid errors in future calculations.
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, and educators seeking to clarify common mistakes in solving exponential integrals.

matt222
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Homework Statement



integrate the function F(t)=1-exp(-∫1/t+2 dt) limit of integration from 0 to t

Homework Equations





The Attempt at a Solution



F(t)=1-exp(-ln(t+2)+ln2)
=1-exp(ln(2-t))*exp(ln2)
=1+2t-4
=2t-3

what do you think about my solutions?
 
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matt222 said:

Homework Statement



integrate the function F(t)=1-exp(-∫1/t+2 dt) limit of integration from 0 to t

Homework Equations





The Attempt at a Solution



F(t)=1-exp(-ln(t+2)+ln2)
=1-exp(ln(2-t))*exp(ln2)
=1+2t-4
=2t-3

what do you think about my solutions?

I think it is full of mistakes. For one thing, it isn't clear whether your original exponential is[tex]e^{-\int {\frac 1 t + 2}\, dt}\hbox{ or } e^{-\int \frac{1}{t+2}\,dt}[/tex] In your first step you have treated it both ways and you are careless with your - signs and simplification. Try again.
 

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