Integration Question (In a loop)

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SUMMARY

The discussion focuses on integrating the function e^x * sin(x) using integration by parts. The user initially sets u = e^x and dv = sin(x)dx, leading to a recursive loop in the integration process. A solution is provided, demonstrating that after the first integration by parts, the integral can be expressed as a combination of e^x * cos(x) and e^x * sin(x), ultimately allowing the user to solve for the integral. The key takeaway is that recognizing the loop enables the application of algebraic manipulation to derive the final result.

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Hyari
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Homework Statement


e^x * sin(x)


Homework Equations


uv - integral vdu


The Attempt at a Solution


FIRST, I set u = e^x, du = e^x, dv = sin(x)dx, v = -cos(x)

Using, uv - integral vdu

e^x * -cos(x) - [ e^x * -cos(x)dx

-e^x * cos(x) + [ e^x * cos(x)

Now I'm stuck... if I keep integrating... I'll keep going in a loop of sin/cos(x) and e^x.

Am I going about this in the wrong way?
 
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You don't actually state that you are trying to integrate exsin(x) but I will assume that!

One thing that is confusing you is that you are not writing out full equations!

After your first integration by parts, you get
[tex]\int e^x sin(x)dx= -e^x cos(x)+\int e^x cos(x) dx[/tex]

Now let u= ex, dv= cos(x), so that du= exdx and v= sin(x) and you get
[tex]\int e^x sin(x)dx= -e^x cos(x)+ e^x sin(x)- \int e^x sin(x)dx[/tex]

Is that the "loop" you mean? Now solve that equation for
[tex]\int e^x sin(x)dx[/tex]!
 
[tex]\sin x= \mathfrak{Im} \left(e^{ix}\right)[/tex]

and the integral becomes a simple exponential.
 

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