With this particular problem you are given the functions y=x[tex]^{2}[/tex], y=4, and y=b.(adsbygoogle = window.adsbygoogle || []).push({});

The object is to solve for a value of b that will split the area between y=4 and y=x[tex]^{2}[/tex] in half.

[PLAIN]http://www4c.wolframalpha.com/Calculate/MSP/MSP263419aghg2f97i2944e0000580a2hgi735b957c?MSPStoreType=image/gif&s=42&w=399&h=201 [Broken]

The approach I took was to include y=b in the integral, and then subtract the top half from the bottom half and equate that to zero.

[tex]\int_{-2}^{2} {(4-x^2-b)}\ = \int_{-2}^{2} {(b-x^2)}[/tex]

All I did then was solve the integrals, and isolate b to get an answer of 4. However the answer is 4^2/3. I'm also stuck on a similar problem where I need to solve for a constant where two functions have to enclose a specific area.

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# Homework Help: Integration/Solving A Constant To Divide An Area

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