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The intensity of light I in the fraunhofer diffraction patter of a single slit is

I=I_{0}(sin[itex]\gamma[/itex]/[itex]\gamma[/itex])^{2}where

[itex]\gamma[/itex]=[itex]\pi[/itex]asin[itex]\theta[/itex]/[itex]\lambda[/itex]

Show that the equation for the vaules of [itex]\gamma[/itex] at which I is maximum is tan[itex]\gamma[/itex]=[itex]\gamma[/itex]

well, intensity isapproxiamatelymax as follows

I_{m}=I_{0}/[(m+1/2)^{2}[itex]\pi[/itex]^{2}]

and for m=1... I_{m}=0.0472I_{0}

m=2....I_{0}=0.0165I_{0}

but i have no clue how to "show" that tan[itex]\gamma[/itex]=[itex]\gamma[/itex] at the max intensity??

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# Homework Help: Intensity of light in Fraunhofer diffraction pattern

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