- #1

Ravenatic20

- 30

- 0

I need to solve this using IbP. I made the following:

[tex]u = (ln x)^2[/tex]

[tex]du = (\frac{2 ln x}{x}) dx[/tex]

[tex]dv = x^2 dx[/tex]

[tex]v = \frac{x^3}{3}[/tex]

So I get:

[tex](ln x)^2 (\frac{x^3}{3}) \|_{1} ^{2e}[/tex][tex]- \int_{1} ^{2e} (\frac{x^3}{3}) 2 ln x dx[/tex]

(not sure how to make this look right)

Is this right?

Where do I go from here? Thanks