Does Heating a Gas Under Constant Pressure or Volume Affect Its Internal Energy?

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SUMMARY

Heating two identical volumes of an ideal gas to 100°C results in the same internal energy for both samples, regardless of whether the heating occurs under constant pressure or constant volume. The internal energy of an ideal gas is defined by the equation 3NkT/2, where N is the number of particles and T is the temperature. Although additional heat is required for the constant pressure scenario to account for the PdV work, the final internal energies remain equal due to the identical temperature and particle count.

PREREQUISITES
  • Understanding of the ideal gas law
  • Familiarity with thermodynamic concepts such as internal energy
  • Knowledge of the relationship between heat, work, and energy
  • Basic grasp of the equations governing ideal gases, specifically 3NkT/2
NEXT STEPS
  • Study the ideal gas law and its applications in thermodynamics
  • Learn about the first law of thermodynamics and its implications for heat and work
  • Explore the concept of PdV work in detail
  • Investigate the differences between heating under constant pressure and constant volume
USEFUL FOR

Students of thermodynamics, physics enthusiasts, and anyone studying the properties of gases and their energy transformations.

Alvine
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Homework Statement
I have two identical volumes of gas, and I heat them both to 100 C, one under constant pressure, one under constant volume. Which has more internal energy after the process?



The attempt at a solution
I believe that they both have the same as the extra heat you have to put into the system at constant pressure to do the expansion is lost as work. But is it more complicated than this as T is changing?

Thanks
 
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I think you're right. The internal energy of an ideal gas is just 3NkT/2, so since the two samples have the same N and the same T after heating them, they have the same internal energy. As you say, you have to put more heat into the constant pressure sample to source the PdV work, but the final internal energies should be the same.
 

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