1. We have some gas in a container at high pressure. The volume of the container is 469 cm^3. The pressure of the gas is 2.52*10^5 Pa. We allow the gas to expand at a constant temperature until its pressure is equal to the atmospheric pressure, which at the time is .857*10^5 Pa. (a) Find the work (J) done on the gas. (b) Find the change of internal energy (J) of the gas. (c) Find the amount of heat (J) we added to the gas to keep it at constant temperature. Be sure to include the right signs on the answers. 2. E=ΔQ+W PV=nRT 3. I know that the work done on teh system is equal to 0 because the volume of the gas does not change. This means that the change in internal energy is equal to the change in heat of the system. However, I don't think I can use PV=nRT because the system does not have a constant pressure. I am not sure how to find the change in internal energy.