- #1
endy_kami
- 5
- 0
what are the internal force in the hinged member 1-4?
Internal forces in members of structure
- Thread starter endy_kami
- Start date
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SUMMARY
The discussion focuses on determining internal forces in a symmetric hinged structure consisting of members 1-4. Participants emphasize the importance of using the force method, displacement method, or matrix stiffness method to accurately calculate the forces. Initial calculations provided by one user were incorrect, leading to a correction where the expected forces were N1=0.4P, N2=0.3P, N3=0.2P, and N4=0.1P. The conversation highlights the necessity of understanding axial deformation equations and the physical interpretation of structural diagrams.
PREREQUISITES- Understanding of statically indeterminate structures
- Familiarity with axial deformation equations
- Knowledge of matrix stiffness method
- Experience with structural analysis software or tools
- Research the force method for analyzing statically indeterminate structures
- Learn about the displacement method in structural analysis
- Study the matrix stiffness method in detail
- Explore examples of axial deformation calculations in structural engineering
Structural engineers, civil engineering students, and anyone involved in analyzing and designing statically indeterminate structures will benefit from this discussion.
- #2
afreiden
- 114
- 3
Interesting problem.
I've attached an image that illustrate my thoughts on how to go about solving it.
I'm assuming the beam is "rigid" and the bars all have the same "stiffness."
Take a look at the image.
Finding the bar forces in the first step is trivial, as the structure is symmetric.
Once you've found the bar forces from step 1 and the bar forces from step 2 (based on my attached image), you can sum them to arrive at your solution.
I drew a red arrow pointing at the second step in the process, which I think needs further explanation. You may find example #2 useful on this website: http://utsv.net/mechanics-of-materials/2-statically-indeterminate-structure-axial
Hope that helps
I've attached an image that illustrate my thoughts on how to go about solving it.
I'm assuming the beam is "rigid" and the bars all have the same "stiffness."
Take a look at the image.
Finding the bar forces in the first step is trivial, as the structure is symmetric.
Once you've found the bar forces from step 1 and the bar forces from step 2 (based on my attached image), you can sum them to arrive at your solution.
I drew a red arrow pointing at the second step in the process, which I think needs further explanation. You may find example #2 useful on this website: http://utsv.net/mechanics-of-materials/2-statically-indeterminate-structure-axial
Hope that helps
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- #3
endy_kami
- 5
- 0
tx a lot I'll try it
- #4
endy_kami
- 5
- 0
dear afreiden,
I've tried the clue that you've given me
I found N1=0,6P N2=0,3P N3=0,03P N4=0,07P
but the answer should be N1=0,4P N2=0,3P N3=0,2P N4=0,1P (according to the writer)
the writer said use the force method or displacement method or
the matrix stiffness method, any idea?
I've tried the clue that you've given me
I found N1=0,6P N2=0,3P N3=0,03P N4=0,07P
but the answer should be N1=0,4P N2=0,3P N3=0,2P N4=0,1P (according to the writer)
the writer said use the force method or displacement method or
the matrix stiffness method, any idea?
- #5
afreiden
- 114
- 3
Show us your work and we can help. Your answer immediately looks wrong to me since I'd expect the forces to be larger in the rods that are nearer to the point of load application. In the author's solution this is indeed the case.
- #6
endy_kami
- 5
- 0
please find attached on how I got to that answer
- #7
afreiden
- 114
- 3
Your equation that you wrote at the top right of your page (I think it might be labeled (1) ) is definitely wrong.
In general, I see several procedural mistakes.In step 1, all bar forces should be the same.
In step 2:
What is your value of "M" ?
How did you determine that N1=2N2? (I expect to see some axial deformation equations)
Do you understand how I was able to draw that triangle?
Your triangle at the bottom of your page does not make physical sense.
In general, I see several procedural mistakes.In step 1, all bar forces should be the same.
In step 2:
What is your value of "M" ?
How did you determine that N1=2N2? (I expect to see some axial deformation equations)
Do you understand how I was able to draw that triangle?
Your triangle at the bottom of your page does not make physical sense.
- #8
endy_kami
- 5
- 0
can you show me how to get to the right answer than?
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