Invariance of quadratic form for unitary matrices

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SUMMARY

Unitary matrices, denoted as ##U##, preserve the quadratic form ##|x_{1}|^{2} + |x_{2}|^{2} + \cdots + |x_{n}|^{2}##, confirming that if ##x' = Ux##, then ##|x'|^{2} = |x|^{2}##. The proof utilizes the relationship ##|x'|^{2} = (Ux)^{\dagger}(Ux) = x^{\dagger}U^{\dagger}Ux = x^{\dagger}x = |x|^{2}##, demonstrating the invariance of the quadratic form under unitary transformations. The discussion highlights the importance of understanding the Hermitian transpose notation in this context.

PREREQUISITES
  • Understanding of unitary matrices and their properties
  • Familiarity with quadratic forms in linear algebra
  • Knowledge of Hermitian transpose notation
  • Basic concepts of complex vector spaces
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Mathematicians, physicists, and students studying linear algebra or quantum mechanics who seek to understand the properties of unitary matrices and their applications in preserving quadratic forms.

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Homework Statement



Show that all ##n \times n## unitary matrices ##U## leave invariant the quadratic form ##|x_{1}|^{2} + |x_{2}|^{2} + \cdots + |x_{n}|^{2}##, that is, that if ##x'=Ux##, then ##|x'|^{2}=|x|^{2}##.

Homework Equations



The Attempt at a Solution



##|x'|^{2} = (x')^{\dagger}(x') = (Ux)^{\dagger}(Ux) = x^{\dagger}U^{\dagger}Ux = x^{\dagger}x = x^{2}##.

Am I correct?
 
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failexam said:
Am I correct?
Yes. (Although I always need to get used to the physicist's notation for the Hermitian transpose. :wink:)
 
Thanks!

I always wish I could see from the mathematician's point of view, being as I am from a Physics background. :smile:
 

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