Inverse Chi Square: Rejecting Null Hypothesis at α=5%, 9DF

AI Thread Summary
To reject the null hypothesis at α = 5% with 9 degrees of freedom, one must reference a chi-square distribution table to find the critical value. The discussion clarifies the need to understand whether the question pertains to the inverse chi-square distribution or the standard chi-square statistic. It emphasizes the importance of knowing the probability density function (PDF) of the distribution being analyzed. A numerical routine may be necessary to solve for the cumulative probability associated with the chi-square statistic. Ultimately, access to a table of chi-square statistics and their probabilities is essential for determining the critical value needed for hypothesis testing.
MadViolinist
Messages
18
Reaction score
0
How can I determine what the smallest value of a χ2 statistic must be to reject the null hypothesis at α = 5%, for a distribution with 9 degrees of freedom? Thanks in advance.
 
Physics news on Phys.org
MadViolinist said:
How can I determine what the smallest value of a χ2 statistic must be to reject the null hypothesis at α = 5%, for a distribution with 9 degrees of freedom? Thanks in advance.

It's not clear from your question whether you asking about the inverse chi square distribution or simply asking about how to determine the correspondence between the chi square value and alpha.

In the first case, there are two definitions of the inverse chi square distribution. One is the chi square of 1/X for \nu degrees of freedom and the second is the chi square of \nu / X for \nu degrees of freedom.
 
Hey MadViolinist and welcome to the forums.

Following on from what SW VandeCarr said, do you know the PDF of the distribution you are working with (chi-square if you are using a chi-square statistic) and how you solve (using a numerical routine) the value of a cumulative probability?
 
Hey all:
I just found out that the question I was asking required the use of a table of corresponding X^2 statistics and their probabilities (which I was not given). Thanks for your time anyway.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

Similar threads

Back
Top