Inverse function and fourier series

In summary, the conversation discusses the possibility of obtaining the inverse function of a Fourier series by reflecting it through the line y=x. However, this approach may not work for complex functions and the problem of finding the reciprocal of a Fourier series remains a difficult problem.
  • #1
zetafunction
391
0
let be the Fourier expansion of the function

[tex] f(x) = \sum_{m=-\infty}^{m=\infty}c_{m} exp(imx) [/tex]

valid on the interval (-1,1) , from this can we obtain the inverse function

[tex] f^{-1} (x) [/tex] by reflection of the Fourier series through the line y=x ??
 
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  • #2
can we obtain the inverse function f(-1)(x) by reflection of the Fourier series through the line y=x ??
Since exp(imx)=cos(mx)+i sin(mx), the function f(x) is complexe z=f(x)
Formally, the inverse function would not be f(-1)(x) but rather x=f(-1)(z)
What do you mean in writing "by reflection through the line y=x " ?
This would have a sens in case of reals y=f(x) and x=f(-1)(y). Presently it is not a real y, but a complex z instead of y.
What do you reflect through the line y=x ? Is it the curve representing y(x)= real part of z as a function of x ?, or is it the curve representing y(x)= imaginary part of z as a function of x ? or is it the curve representing y(x)= module of z as a function of x ? or is it the curve representing y(x)= argument of z as a function of x ?
 
  • #3
assume function f(x) is real, then the Fourier series will include sines and cosines only .. but no exponential quantities.
 
  • #4
assume function f(x) is real, then the Fourier series will include sines and cosines only .. but no exponential quantities
Sure ! if f(x) is assumed to be real the general terms of the Fourier series will be :
amcos(mx)+bmsin(mx) which is real.
But in the first question this was not the case : The general term was cmexp(i m x) = cm( cos(mx) + i sin(mx) ) which is not real.
So the question was raised in the general case of f(x) complex, even if the coefficients cm are complex (and/or real).
 
  • #5
zetafunction said:
let be the Fourier expansion of the function

[tex] f(x) = \sum_{m=-\infty}^{m=\infty}c_{m} exp(imx) [/tex]

valid on the interval (-1,1) , from this can we obtain the inverse function

[tex] f^{-1} (x) [/tex] by reflection of the Fourier series through the line y=x ??

I'm interested in this as well if anyone has any ideas.
 
  • #6
Well, the problem cannot be raised in terms of reflexion through the line y=x on a real space.
Seriously, expressing the reciprocal of a Fourier series is a very difficult problem, still open :
http://www.jstor.org/pss/2031811
http://www.jstor.org/pss/2034097
 
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What is an inverse function?

An inverse function is a mathematical operation that reverses the effect of another function. It takes the output of a function as its input and produces the original input value.

How do you find the inverse of a function?

To find the inverse of a function, you can follow these steps:

  • Write the function as y = f(x).
  • Switch the roles of x and y, so that x = f(y).
  • Solve for y in terms of x.
  • The resulting equation will be the inverse function, denoted as f-1(x).

What is a Fourier series?

A Fourier series is a mathematical representation of a periodic function as a sum of sinusoidal functions. It is used to break down complex functions into simpler components for analysis and modeling.

How do you calculate a Fourier series?

To calculate a Fourier series, you can follow these steps:

  • Identify the period of the function.
  • Write the function as a sum of cosines and sines, using the appropriate coefficients.
  • Use trigonometric identities to simplify the coefficients.
  • Integrate the function and solve for the coefficients.
  • The resulting equation will be the Fourier series of the function.

What is the relationship between inverse functions and Fourier series?

Inverse functions and Fourier series are related in that they are both used to analyze and represent functions. Inverse functions can be used to find the input value for a given output, while Fourier series can be used to break down a function into simpler components. In some cases, the inverse function of a Fourier series can be used to reconstruct the original function.

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