Can a Non-Invertible Function Become Invertible in Certain Intervals?

The verb to revert does not have a corresponding adjective. So, in summary, the discussion is about whether a function that is not invertible can become invertible in certain intervals or if it can never be called invertible. It is possible for a function to become invertible in a specific interval, but technically it would not be the same function. This is because the domain of a function is just as important as its formula. For example, the function f(x)=x^2 is not invertible, but if we restrict the domain to non-negative real numbers, its inverse is √x. Similarly, if we restrict the domain to non-positive real numbers, its inverse is -√x. However, the domain of a function
  • #1
ZeroPivot
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can a function that's not inversable be inversible in certain interwalls. is it ok to say its inversable in this specific intervall or can't the function ever be called inversible?
 
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  • #2
Yes, but technically, it wouldn't be the same function.

For example, [itex]f(x)= x^2[/itex]is not "invertible" because it is neither "one to one" nor "onto". However, if we restrict the domain to the "non-negative real numbers" then its inverse is [itex]\sqrt{x}[/itex]. If we restrict the domain to the "non-positive real numbers" then its inverse is [itex]-\sqrt{x}[/itex].

However, the domain of a function is as much a part of its definition as the "formula". That is, "[itex]f(x)= x^2[/itex], for x any real number", "[itex]g(x)=x^2[/itex], for x any non-negative real number", and [itex]h(x)= x^2[/itex], for x any non-negative real number" are three different functions. The first does not have an inverse, the last two do.
 
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  • #3
HallsofIvy said:
Yes, but technically, it wouldn't be the same function.

For example, [itex]f(x)= x^2[/itex]is not "invertible" because it is neither "one to one" nor "onto". However, if we restrict the domain to the "non-negative real numbers" then its inverse is [itex]\sqrt{x}[/itex]. If we restrict the domain to the "non-positive real numbers" then its inverse is [itex]-\sqrt{x}[/itex].

However, the domain of a function is as much a part of its definition as the "formula". That is, "[itex]f(x)= x^2[/itex], for x any real number", "[itex]g(x)=x^2[/itex], for x any non-negative real number", and [itex]h(x)= x^2[/itex], for x any non-negative real number" are three different functions. The first does not have an inverse, the last two do.

can i say function y=x^2 is inversible for x E [0 ,4] ?
 
  • #4
Yes, the function
[tex] f: [0,4]\to [0,16],\ x\mapsto x^2 [/tex]
is an invertible function because of the domain that has been specified (also it needs to have the right codomain, or it won't be an onto function, but that's more of a technicality that is washed away by restricting the codomain to whatever the range is)
 
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  • #5
ZeroPivot said:
can i say function y=x^2 is inversible for x E [0 ,4] ?
"Inversible" is not a word - the one you want is invertible.
 
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  • #6
So why is "reversible" a word and not "revertible"?
 
  • #7
Mark44 said:
"Inversible" is not a word - the one you want is invertible.

Possibly because the adjectives invertible and reversible come from the verbs to invert and to reverse, respectively.
 

1. What is an inverse function?

An inverse function is a mathematical operation that undoes another function. It is essentially the "reverse" of a function and is denoted by f^-1(x).

2. How do you determine if a function has an inverse?

A function must be one-to-one (injective) in order to have an inverse. This means that each input corresponds to a unique output and no two inputs have the same output.

3. What is the notation used for inverse functions?

The notation for an inverse function is f^-1(x), with the "^-1" indicating that it is the inverse of the original function f(x).

4. Can any function have an inverse?

No, not all functions have an inverse. Only one-to-one functions have inverses.

5. How do you find the inverse of a function?

To find the inverse of a function, switch the x and y variables and solve for y. The resulting equation will be the inverse function, f^-1(x).

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