Inverse Tan Function Range: (-pi/2, pi/2)

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The range of the inverse tangent function, y = inverse tan(2x), remains (-π/2, π/2), similar to the standard inverse tangent function. The transformation of 2x affects the domain but not the range. As x approaches negative infinity, 2x also approaches negative infinity, leading tan⁻¹(2x) to approach -π/2. Conversely, as x approaches positive infinity, 2x approaches positive infinity, causing tan⁻¹(2x) to approach π/2. Therefore, the range of inverse tan(2x) is confirmed to be (-π/2, π/2).
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Homework Statement



State the range

y=inverse tan( 2x)

The Attempt at a Solution



The original range of inverse tan is ( -pi/2, pi/2)

Should tan inverse (2x) have (-pi, pi) as its range?
 
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No. 2x changes x values, the domain, not the range. The range of tan-1(x) is (-pi/2, pi/2) because as x goes to negative infinity, tan-1[/sup](x) goes to -pi/2 and as x goes to infinity, tan-1(x) goes to pi/2.

As x goes to -infinity, what does 2x go to? What does tan-1
(2x) go to?
As x goes to infinity, what does 2x go to? What does tan-1
(2x) go to?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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