Inverting Op Amp Circuit: Calculating Output Voltage with Feedback Loop

Click For Summary

Discussion Overview

The discussion revolves around calculating the output voltage of an inverting operational amplifier circuit with a feedback loop. Participants are addressing the relationships between input voltages, resistances, and currents in the circuit, while attempting to derive an expression for the output voltage.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses difficulty in eliminating two currents to derive an expression for the output voltage, proposing equations for the currents through the feedback loop.
  • Another participant identifies a mistake in the circuit drawing, specifically regarding the placement of ground in relation to the feedback resistor.
  • A different participant suggests considering additional properties of operational amplifiers in negative feedback situations that may aid in solving the problem.
  • Another reply critiques an equation presented by the first participant, indicating that it incorrectly mixes output and input voltages, and suggests neglecting the influence of one resistor based on the assumption of an ideal amplifier.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there are differing views on the correctness of the equations and the assumptions made regarding the circuit components.

Contextual Notes

Participants express uncertainty about how to relate various voltages and currents in the circuit, and there are unresolved assumptions regarding the ideal behavior of the operational amplifier and the influence of certain resistors.

AdkinsJr
Messages
148
Reaction score
0

Homework Statement



Write output voltage in terms of input voltages for the circuit drawn.

I drew the circuit and then feed back loop.
circuit-9_4 (1).png

Homework Equations



Ohms Law V=IR
Basic Properties of Op Amps (ideal), voltages are assumed equal at both inputs...

The Attempt at a Solution



The difficulty is that there should be two currents that need defining, but I'm not sure how to eliminate both of them. I wrote two equations for the current through the feedback loop and then equated to write Vout in temrs of the resistances and Va.

I_a = \frac{V_{out}-V_a}{R_2}
I_a = \frac{V_a-V_{out}}{R_1}
V_{out}=\frac{V_a-V_{in}}{R_1}R_2 +V_a

I can't figure out how to write Va in terms of Vin and the resistances at this point. The only other relationships between Va and other quantities come from the fact that V_b=I_bR_3 which means that V_a=I_bR_3 also, but I still need to get rid of the current Ib now, so that doesn't help much. I can't figure out what I'm missing. Any help would be great.
 
Physics news on Phys.org
There's a mistake in the feed back loop in my drawing, the ground at the end of R2 should not be there, that should be Vout.
 
You've listed one useful property for the op-amp in a negative feedback situation. What other property might be useful?
 
Have a look on the second equation. Obviously, it is wrong (Vout mixed-up with Vin).
More than that, you can forget the influence of R3 (because an ideal amplifier with infinite input resistance is assumed). Hence, you can set Va=Vb=0.
 

Similar threads

Replies
15
Views
3K
Replies
34
Views
4K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 44 ·
2
Replies
44
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K