Investigate Newtons Laws. Intro Physics

[Kmcquiggan]

Homework Statement

Two tugboats are pulling on a large log, as shown in figure. The log has a mass of 250kg and is initially at rest. How far has tug boat gone after 10s?

Relevant Equations

v_2=v_1+a∆, c= √(a^2+b^2-2abcos°), sine law=sinA/a=sinB/b=sinC/c, a=F_net/m

 

[BvU]

Is there a question in this ?

Have you read the guidelines ?

 

[Kmcquiggan]

yes the question is in the question area as well as in the first picture and my attempt is in the second image which is a screen shot of my laptop screen.

 

[ehild]

Problem Statement: Two tugboats are pulling on a large log, as shown in figure. The log has a mass of 250kg and is initially at rest. How far has tug boat gone after 10s?
Relevant Equations: v_2=v_1+a∆, c= √(a^2+b^2-2abcos°), sine law=sinA/a=sinB/b=sinC/c, a=F_net/m

What is your c= √(a^2+b^2-2abcos°)? You need the sum of the two forces, but you calculated the difference.

 

[Doc Al]

Looks like you tried to use the law of cosines to find the net force: Better recheck your arithmetic.

Once you find the acceleration, how would you find the distance traveled?

 

[Kmcquiggan]

°I went back and checked and see that I made a calculation wrong C= 1163.72 round to 1164. and I then reput the info into sine law and got Fnet= 20°-10° which left [W 10 ° N] than I figured a = Fnet/m = 1164/250=4.656
I used the distance formula which is:
d=vi8t + 1/2*a*t^2 = d= 0+(.5)(4.66)(100) =233m
So therefore the tg boats would be 233m after 10 sec is this getting closer?

 

[Doc Al]

I made a calculation wrong C= 1163.72 round to 1164.

That looks better.

I then reput the info into sine law and got Fnet= 20°-10° which left [W 10 ° N]

?? Why are you using the sine law?

than I figured a = Fnet/m = 1164/250=4.656

Looks OK. As does the rest of your work.