Investigating Specific Heat Capacity with Boiling & Warm Water

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Homework Help Overview

The discussion revolves around a lab experiment investigating specific heat capacity using boiling water and warm water. The original poster describes their methodology involving the introduction of lead into water and calculations based on temperature changes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question the mass used in calculations, the final temperature recorded, and the appropriateness of using lead's mass with water's specific heat. There are inquiries about the clarity of the experimental procedure and the initial conditions of the experiment.

Discussion Status

Some participants have offered guidance on potential errors in the original poster's calculations and assumptions. There is an ongoing exploration of the methodology and the accuracy of the temperature measurements, with no explicit consensus reached.

Contextual Notes

The original poster mentions constraints related to a substitute teacher and a lack of clarity in their explanation of the procedure. There is also a reference to textbook values for specific heat capacity that may influence the discussion.

pdot
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I am doing a lab about specific heat. i have a cup of boiling water which i put 5 metals into, and a cup of warm water which sits at 22 degrees celsius. i am to record the difference in temperature as i am using the equation Q = mc (delta) T for part one, and then i am using the equation C = Q/m (delta ) t for part two.

For the first equation i will be using the mass of .059kg ( weight of Lead ), 4180 J/ kg degrees celsius ( i put all the metals into a boiling cup of water ) and the change of water tempterature which started at 22 degrees and went to 23 when i put the lead into the cup of water.

Q = mc (delta) t.
Q = (.059)(4180)(22-23)
please correct if i have made a mistake.
Q = -246

for the second equation i am using -246 for Q. .059kg for mass and (23-100) for change of temperature.

C = Q/m (delta ) t.
C = (-246)(.059)(23-100)
C = (-14.514)(-77) = 1117 J/KG degrees celsius. to me this is not right, and i had a substitute on friday so i couldn't ask. i also got another answer for the second equation which was 54 J/kg degrees celsius.
could someone please tell me what I am doing wrong.
Preston.
 
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For one, you said you put in all the pieces of lead into the cup, did each piece have a mass of 0.059 kg or did all in total have 0.059 kg?

Secondly, to use Q=mcΔT for the first part, you measured the final temperature of the water as 23°C after putting lead at 100°C in the water. Usually the final temperature of the water would not be that low.

In that same equation, the 'm' would be the mass of the water, you used the mass of the lead.


I think you main problem lies in the fact that you recorded the final temperature of the water ( and hence lead incorrectly). I based this solely on the fact that you put 100°C lead into 22°C water and only saw a temperature rise of 23°C.
 
pdot said:
Q = mc (delta) t.
Q = (.059)(4180)(22-23)
please correct if i have made a mistake.
Q = -246

Why are you using the mass of lead with the specific heat of water? Did you measure the volume or mass of water? "A cup" is probably not the volume, since you're most likely working with metric units...

Also, you haven't exactly explained the procedure in a clear fashion. Was the idea of putting the lead into boiling water to raise its temperature to a known starting value (100C) before dropping it into the lukewarm water?
 
Ok thanks guys, and i am sorry if i have not fully explained. i guess i should pay more attention in class. and i will work on explaining myself more on posts to come.
 
yes rock freak, my equation is not supposed to be perfect it is supposed to come close the the specific heat. i got 136, the answer in the book is 130. thank you guys again
 
for lead ^
 

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