Ion Exchange Between Salts in a Solution

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When two alkaline Earth metal-halide salts, such as potassium iodide and sodium chloride, are dissolved in water and the solution is boiled off, the formation of new salts like potassium chloride and sodium iodide is influenced primarily by solubility. As water evaporates, less soluble salts crystallize first, leading to a mixture of salts rather than a complete conversion to just two types. The process does not guarantee that only two salts will remain, as varying concentrations of all four salts can exist depending on their solubility characteristics. Additionally, enthalpies of formation can play a role in determining the stability of the resulting salts, but the primary factor remains solubility. Precipitation reactions can occur even without water removal, depending on the concentrations and interactions of the ions in solution.
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If you have two alkaline Earth metal-halide salts in a solution (for example potassium iodide and sodium chloride), when you boil off the water will you find that new salts (In this case potassium chloride and sodium iodide) have formed? Will the most electronegative and least electronegative ions seek each other out? Will you end up with only two salts at the end, assuming you had equal proportions of the salts at the beginning, or will you end up with various similar concentrations of 4 salts?
 
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What will happen depends mostly on solubilities - less soluble salts will start to crystallize first, followed by the less soluble ones.

http://en.wikipedia.org/wiki/Fractional_crystallization_(chemistry )
 
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Thanks.
 
Also, do enthalpies of formation have any meaningful effect on which salts result? Could you theoretically have a precipitation reaction if you don't remove the water?
 
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