Irms, Vrms and power calculations

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SUMMARY

The discussion focuses on calculating Irms and I*rms given a Vrms of 120 V at an angle of 30° and an impedance Z of 10 Ω. The correct formula for Irms is established as Irms = Vrms / Z, resulting in Irms = 12∠30°. The confusion arises around I*rms, which is clarified as the complex conjugate of the current, requiring the angle to be inverted to -30°. Thus, I*rms is determined to be 12∠-30°.

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Homework Statement



Basically, I need to understand how to calculate Irms and I*rms given a Vrms and an impedance Z.

Example question:
Given Vrms = 120 V at an angle of 30° and an impedance of Z = 10 Ω, find Irms and I*rms.


Homework Equations



How exactly do I solve for Irms and I*rms?


The Attempt at a Solution



I figure that Irms = Vrms / Z. However I am a bit confused as to the I*rms.

From my notes, I would imply that I just flip the sign of the angle, but this does not seem right.

My attempt:

Irms = Vrms/Z = 120angle30/10angle0 = 12angle30
And for I*rms, just flip the sign of the angle: 12angle-30
 
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NoConflict said:

Homework Statement



Basically, I need to understand how to calculate Irms and I*rms given a Vrms and an impedance Z.

Example question:
Given Vrms = 120 V at an angle of 30° and an impedance of Z = 10 Ω, find Irms and I*rms.


Homework Equations



How exactly do I solve for Irms and I*rms?


The Attempt at a Solution



I figure that Irms = Vrms / Z. However I am a bit confused as to the I*rms.

From my notes, I would imply that I just flip the sign of the angle, but this does not seem right.

My attempt:

Irms = Vrms/Z = 120angle30/10angle0 = 12angle30
And for I*rms, just flip the sign of the angle: 12angle-30

Yup. basically that's it. I* represents the complex conjugate, which for a complex number means that the sign of the imaginary component of the number is inverted. This has the effect of inverting the sign of the angle in polar form.
 

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