Is 0.5sin2x the Fourier Series of sinx*cosx?

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SUMMARY

The Fourier series representation of the function sin(x)cos(x) is definitively 0.5sin(2x). This conclusion is supported by the trigonometric identity that states sin(x)cos(x) equals 0.5sin(2x). According to the uniqueness theorem of Fourier series, this representation is valid as all other terms in the series are zero, confirming that no additional summation is necessary.

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  • Knowledge of the uniqueness theorem in Fourier analysis
  • Basic calculus concepts related to periodic functions
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My professor said the Fourier series of sinx*cosx is simply 0.5sin2x.

Is this right?? Is there no summation??

I don't understand why .. Help!
 
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She's right, by uniqueness of Fourier series.

Trig identity for sin2x shows that sin x*cos x=0.5sin2x.

This is the form of a Fourier series, hence the unique. (All the other infinitely many terms are 0.)
 

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