Is a highly efficient Carnot engine suitable for use as a refrigerator and why?

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Homework Help Overview

The discussion revolves around the efficiency of a Carnot engine and its suitability as a refrigerator. Participants explore the relationship between the efficiency of a Carnot engine and the coefficient of performance when it operates as a refrigerator, questioning the implications of high efficiency in this context.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants attempt to derive the relationship between the efficiency and the coefficient of performance, questioning the validity of their calculations. Some express confusion regarding the implications of high efficiency for the Carnot engine's performance as a refrigerator.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants provide insights into the theoretical aspects of Carnot cycles, while others express uncertainty about the sufficiency of their explanations. There is no explicit consensus, but several productive lines of reasoning are being examined.

Contextual Notes

Participants note that the temperatures involved are fixed, and there is a discussion about the implications of high efficiency on the heat transfer dynamics between the reservoirs. The constraints of the Carnot cycle and its reversible nature are also under consideration.

Nusc
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Show that the relationship betwee efficiency (n) of a Carnot engine and the coefficient of performance (w) of the same engine when operated as a refrigerator is given by nw= Tc/Th

Is a Carnot engine whose efficiency is very high particularly suited as a refrigerator? Why?

Well we know that for Carnot engines the efficiency is n = [Th-Tc]/Th
and that the coefficieny of performance for a refrigerator is Qh/w = Qh/(Qh-Qc)

nw = (1 - Tc/Th)(Qh-Qc)
= Qh - TcQh/Th - Qc +TcQc/Th
=/= Tc/Th

What is wrong?
 
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Nusc said:
Show that the relationship betwee efficiency (n) of a Carnot engine and the coefficient of performance (w) of the same engine when operated as a refrigerator is given by nw= Tc/Th

Is a Carnot engine whose efficiency is very high particularly suited as a refrigerator? Why?

Well we know that for Carnot engines the efficiency is n = [Th-Tc]/Th
and that the coefficieny of performance for a refrigerator is Qh/w = Qh/(Qh-Qc)

nw = (1 - Tc/Th)(Qh-Qc)
= Qh - TcQh/Th - Qc +TcQc/Th
=/= Tc/Th

What is wrong?
The coefficient of performance of a refrigerator is given by \omega = Q_C/W and the efficiency of a heat engine is: \eta = W/Q_H

So \eta\omega = \frac{Q_C}{Q_H}

In a Carnot cycle, \Delta S = 0 so:
\frac{Q_H}{T_H} - \frac{Q_C}{T_C} = 0
and:
\frac{T_C}{T_H} = \frac{Q_C}{Q_H}

AM
 
Is a Carnot engine whose efficiency is very high particularly suited as a refrigerator? Why?

A high efficiency would imply that Qc >> Qh based on the result Tc/Th for part a).

But what specific justification is necessary to explain that for Carnot engines?
 
Nusc said:
Is a Carnot engine whose efficiency is very high particularly suited as a refrigerator? Why?

A high efficiency would imply that Qc >> Qh based on the result Tc/Th for part a).

But what specific justification is necessary to explain that for Carnot engines?
A Carnot engine and a Carnot refrigerator both employ the reversible (Carnot) cycle. The refrigerator just reverses the direction of the heat flow by making an infinitessimal change in the starting conditions.

In the question, the temperatures are fixed. High efficiency does not mean that Qc >> Qh. This can never be the case. Whatever heat is removed from the cold reservoir is transferred to the hot reservoir (along with the added work which is converted to heat as well).

The reversible cycle represents the limit of the efficiency of the ratio of work to heat transfer between two temperatures. In the case of heat moving from hot to cold, the Carnot cycle provides the maximum amount of useable work that can be extracted. In moving heat from cold to hot, the Carnot cycle provides the minimum amount of work that must be added.

Theoretically, you can make a Carnot engine into a Carnot refrigerator by storing all the work output of the engine cycle (say by lifting a weight) and then using that work to reverse the cycle and move the heat from the cold reservoir back to the hot reservoir.

AM
 
Is a Carnot engine whose efficiency is very high particularly suited as a refrigerator? Why?

So how's this, if a Carno engine has a lot of efficiency then we can see from n = 1 - T2/T1 that T2<<T1 so it makes a good refrigerator.
 
Nusc said:
Is a Carnot engine whose efficiency is very high particularly suited as a refrigerator? Why?

So how's this, if a Carno engine has a lot of efficiency then we can see from n = 1 - T2/T1 that T2<<T1 so it makes a good refrigerator.
A Carnot refrigerator is not very efficient if T2<<T1. But it is more effiient than any other refrigerator between those two temperatures.

Between two given temperatures, the Carnot engine is more efficient than any other and the Carnot refrigerator is more efficient than any other refrigerator.

AM
 
Was what I wrote sufficient in answering the question, that's all I ask for. Because you just confused me.
 
Last edited:
Nusc said:
Was what I wrote sufficient in answering the question, that's all I ask for. Because you just confused me.
A Carnot engine is highly efficient only if Th>>Tc. With this temperature difference, a refrigerator (Carnot or otherwise) is not going to be very efficient (ie. in the reverse cycle). I think that is the answer they are looking for. But you can add that the Carnot will be more efficient than any other.

AM
 

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