Phrak said:
...explain why there is an apparent dominance of hydrogen over antihydrogen.
I found this, "It is thought that the primordial nucleons themselves were formed from the quark–gluon plasma from the Big Bang as it cooled below two trillion degrees. A few minutes afterward, starting with only protons and neutrons, nuclei up to lithium and beryllium (both with mass number 7) were formed, but only in relatively small amounts."[1]
and "For reasons that remain uncertain, during the process of leptogenesis there was an excess in the number of electrons over positrons. Hence, about one electron in every billion survived the annihilation process. This excess matched the excess of protons over anti-protons, in a condition known as baryon asymmetry, resulting in a net charge of zero for the universe."[2, 3] which, I gather you are well aware of. You can certainly envision H formation without H-bar from there.
So, I gather what you are asking really boils down to, "Why is it just u quarks (u) and d quarks (d) without u-bar and d-bar (from which H-bar would arise)?"
I don’t know. One could imagine the equivalent of a neutral hexaquark (3u,3d) in the "plasma" freezing out, then decaying into a proton, neutron and electron (plus neutrinos) with no asymmetry unless we blindly insist on designating them
all "matter". It bears repeating, though the term "antimatter" is relatively new, it cannot escape the fact that it reflects directly from
just such a designation "matter", handed down through the
millennia.
Redesignation would have, u as matter, d as antimatter. Since u has half the mass but twice the charge magnitude as d, there is already balance. There is no abundance of u-bar or d-bar because none is called for. Under redesignation, neither conservation of mass, charge, spin nor baryon number is violated. Granted the pile of u’s is not identical to the pile of d’s but neither tips the scales (adding the leptons as needed). It remains typical today that particle decay results in non-twin products, but still follows the conservation laws (i.e. they balance). There is some asymmetry
internally but none
externally.
You might still ask, "Why is u not a positive twin of d?", which would have
both internal and external symmetry. The answer has to be, if u and d were twin:antitwin, they would annihilate. That universe would self destruct. So, it might be argued that a universe with internal asymmetry is the
only type which could arise.
Think about this. How often does an overstretched guitar string break dead center? One side curls clockwise, the other spins oppositely. If you measure closely enough, they never come out to be
exactly equal in length. Yet they still add up to a single, uncurled guitar string. There is no need to suppose a
separate guitar string broken in exactly the opposite way.
We live in a guitar string universe. Rock on!
1]
http://en.wikipedia.org/wiki/Nucleosynthesis
2]
http://en.wikipedia.org/wiki/Electron
3] http://en.wikipedia.org/wiki/Leptogenesis_(physics )