Is dx/dy equal to 1/(dy/dx) in Math Equations?

[madcap_]

I was logged out when trying to post and lost everything


Without the background of the question cause I've lost all the equations and everything, i just needed to know if dx/dy = 1/(dy/dx)

 

[Pengwuino]

Yes for the most part. There are some basic stipulations I believe, but I'll let the mathematicians point that out.

 

[Dick]

Sure, it's true.

 

[madcap_]

The problem:
Youre given

Then it says:

My solution:

First type:

Second type:

It seems to easy to be right.. Though it's part of a worded problem so I could be missing something

 

[Dick]

The problem:
Youre given

Then it says:

My solution:

First type:

Second type:

It seems to easy to be right.. Though it's part of a worded problem so I could be missing something

That basically looks ok to me. Is replacing alpha with c in the second part just a typo?

 

[madcap_]

Yeah, well I used wolfram to input my answers so it's readable and didn't have that symbol handy. It's the symbol for proportion right?

 

[Dick]

Yeah, well I used wolfram to input my answers so it's readable and didn't have that symbol handy. It's the symbol for proportion right?

From what you said in defining dV/dt, it doesn't look like they mean it's 'proportional to'. They are just saying dV/dt is equal to -alpha*(h+R) where alpha is a constant. Not the 'proportional to' symbol. You could simplify (h+R)/(R^2-h^2) a bit.

 

[madcap_]

Thank you for clearing that up Dick.