MHB Is e^x a transcendental function?

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Why The function e^z is transcendental over C(z)?
 
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What the definition of "transcendental function"?
 
A function that its result, f(x) is not can be found by addition, subtraction, division, multiplication, roots and powers operation.
Still, I don't understand.
 
Well, given a value of x, say, $x= \pi$, how would you find f(x)? What is $f(\pi)= e^\pi$? (I can think of two different ways but neither would give an exact numerical value. I wouldn't expect them to because this is an irrational number.)
 
O.K.
In my words, because e with any power of any number is transcedental function...
Right?
 
Well, that's just restating that e^x is a transcendental function isn't it? The "two ways" or evaluating, say, e^\pi are
(1) Use a calculator! The calculator typically uses the "CORDIC" method (https://en.wikipedia.org/wiki/CORDIC)
(2) Evaluate the Taylor's series expansion for e^\pi. That is 1+ \pi+ \frac{\pi^2}{2}+ \frac{\pi^3}{3!}+ \cdot\cdot\cdot for some finite number of terms. Strictly speaking, that is a polynomial calculation. But e^x is NOT a polynomial because the exact value requires the infinite series.
 
A sphere as topological manifold can be defined by gluing together the boundary of two disk. Basically one starts assigning each disk the subspace topology from ##\mathbb R^2## and then taking the quotient topology obtained by gluing their boundaries. Starting from the above definition of 2-sphere as topological manifold, shows that it is homeomorphic to the "embedded" sphere understood as subset of ##\mathbb R^3## in the subspace topology.
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