Is ##\eta## Referring to the Minkowski Metric in Tensor Summation?

  • Thread starter Thread starter sunrah
  • Start date Start date
  • Tags Tags
    Tensors
sunrah
Messages
191
Reaction score
22
sorry solved
 
Last edited:
Physics news on Phys.org
By ## \eta ## are you referring to the Minkowski metric? Also, I assume that only indices that appear once raised and once lowered are being summed over, so that ## \eta^{ii} ## is not to be summed, correct?
 
Geofleur said:
By ## \eta ## are you referring to the Minkowski metric? Also, I assume that only indices that appear once raised and once lowered are being summed over, so that ## \eta^{ii} ## is not to be summed, correct?

thanks, the issue was simply that sometimes I forget we are dealing with components and not whole vectors, matrices etc.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top