Is It Possible to Have Bounded Partial Derivatives Without Differentiability?

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A function can have bounded partial derivatives without being differentiable, as illustrated by the example f(x) = |x|, which has bounded derivatives but is not differentiable at x = 0. The relationship between boundedness of partial derivatives and differentiability is not direct; a function can be differentiable with unbounded derivatives, such as f(x) = x^2. This highlights that boundedness and differentiability are independent properties in calculus. Understanding this distinction is crucial for grasping advanced calculus concepts. The discussion emphasizes the complexity of differentiability beyond just the behavior of derivatives.
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Is it possible to have a function that has bounded paritial derivatives, but is not differential? Can you give me an example? And if possible explain how this is possible?

I am having trouble understanding this calculus concept. Thanks.
 
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I assume that you meant "differentiable" instead of "differential"?

How about f(x) = |x|.
For all x, |f'(x)| \le 1
however, f(x) is not differentiable.

The boundedness of partial derivatives and differentiability don't have much to do with each other. On the other hand, for example, the derivative of f(x) = x2 is unbounded although f(x) is perfectly well differentiable (infinitely often, even).
 
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