Is it possible to solve spring questions with Calculus?

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    Calculus Spring
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SUMMARY

Calculus can be effectively utilized to solve spring-related problems, particularly in the context of simple harmonic motion. In the discussion, a block with a mass of 0.3 kg and a spring constant of 24 N/m is analyzed, revealing that the maximum velocity occurs when the spring is compressed 3.5 cm. The integration of acceleration, which is dependent on distance, is crucial for deriving the equations of motion. The fundamental approach involves using F=ma, where the force is defined by the spring constant multiplied by displacement.

PREREQUISITES
  • Understanding of simple harmonic motion
  • Knowledge of calculus, specifically integration and derivatives
  • Familiarity with Newton's second law (F=ma)
  • Basic concepts of spring mechanics, including spring constant and displacement
NEXT STEPS
  • Learn how to derive the equations of motion for a simple harmonic oscillator
  • Study the integration of acceleration in the context of spring dynamics
  • Explore the relationship between displacement, velocity, and acceleration in harmonic motion
  • Investigate the application of initial conditions in solving differential equations related to springs
USEFUL FOR

Students and educators in physics, engineers working with mechanical systems, and anyone interested in applying calculus to solve problems involving springs and harmonic motion.

docholliday
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I found this on a previous thread and someone mentions that you can use calculus to solve it. I already solved it using the law of conservation and got .027816 m or 2.7 cm, but it's driving me nuts figuring out how to use calculus to solve.

How do I go about integrating acceleration since it's dependent on distance? Please give any insight.

1. A block of mass 0.3 kg and spring constant 24 N/m is on a frictionless surface. If the block is set into motion when compressed 3.5 cm, what is the maximum velocity of the block? How much is the spring compressed when the block has a velocity of 0.19 m/s?
 
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docholliday said:
I found this on a previous thread and someone mentions that you can use calculus to solve it. I already solved it using the law of conservation and got .027816 m or 2.7 cm, but it's driving me nuts figuring out how to use calculus to solve.

How do I go about integrating acceleration since it's dependent on distance? Please give any insight.

1. A block of mass 0.3 kg and spring constant 24 N/m is on a frictionless surface. If the block is set into motion when compressed 3.5 cm, what is the maximum velocity of the block? How much is the spring compressed when the block has a velocity of 0.19 m/s?

Google "simple harmonic oscillator" to find the standard calculus-based solution.

And for a quick preview... You'll start with F=ma, where F is just the spring constant k times the displacement x, and the acceleration a is the second derivative (this is where the calculus comes in) of the displacement with respect to time:
[tex]kx=m\frac{d^2x}{dt^2}[/tex]

Now try plugging in [itex]x=sin(At+B)[/itex], use the initial conditions, solve for A and B, and you'll have the displacement as a function of time. And of course the velocity as a function of time will be the first derivative of that.
 

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