Karpthulu912 Messages 4 Reaction score 0 Thread starter Jan 23, 2017 #1 so the karp is back with another question about math and well this time its not a long homework but rather a genuine question is this possible? (5-i)/i
so the karp is back with another question about math and well this time its not a long homework but rather a genuine question is this possible? (5-i)/i
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 Jan 24, 2017 #2 If you are asking if it's possible to write this expression in the form $a+bi$, yes, it is: $$c=\frac{5-i}{i}$$ Let's multiply this expression by $$1=\frac{i}{i}$$: $$c=\frac{5-i}{i}\cdot\frac{i}{i}=\frac{5i-i^2}{i^2}$$ Now, using the fact that $i^2=-1$, we have: $$c=\frac{5-i}{i}\cdot\frac{i}{i}=\frac{5i-i^2}{i^2}=\frac{5i-(-1)}{-1}=\frac{5i+1}{-1}=-1-5i$$ :D
If you are asking if it's possible to write this expression in the form $a+bi$, yes, it is: $$c=\frac{5-i}{i}$$ Let's multiply this expression by $$1=\frac{i}{i}$$: $$c=\frac{5-i}{i}\cdot\frac{i}{i}=\frac{5i-i^2}{i^2}$$ Now, using the fact that $i^2=-1$, we have: $$c=\frac{5-i}{i}\cdot\frac{i}{i}=\frac{5i-i^2}{i^2}=\frac{5i-(-1)}{-1}=\frac{5i+1}{-1}=-1-5i$$ :D