Is l2 Space Separable and Second Countable?

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Homework Statement



1. Prove that if a metric space (X,d) is separable, then
(X,d) is second countable.2. Prove that \ell^2 is separable.

Homework Equations


The Attempt at a Solution



1. \{ x_1,\ldots,x_k,\ldots \} is countable dense subset. Index the
basis with rational numbers, \{ B(x,r) | x \in A, r \in \mathbb{Q}<br /> \} is countable (countable \times countable).

2. What set is a countable dense subset of \ell^2?
 
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2. Let A = the set of sequences with only finitely many non-zero components(N of them), where each term is a member of the rationals.
We can show that the we can approximate every element of \ell^2 by sequences in A, hence the closure is \ell^2. (The set \ell^2 \ A are the limit points)
If you think about it, between any reals there's a rational number
So for each term, we can get a rational that is of distance \frac{\epsilon}{N} of it.
Then the distance is N*\frac{\epsilon}{N}.

Take limit as N goes to infinity.

It's late here so I'm not really capable of putting all this into nice sentences.
 
1. correct
2. this comes down to the fact that R (or C) is separable; just restrict to rationals and finite sequences (see ninty's reply).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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