Is Light's Speed Truly Constant in All Frames of Reference?

madhumadanan
Messages
1
Reaction score
0
Dear PF i am new to this forum .

Just wanted to clear a doubt about relativity.

consider a inertial system on a light ray moving at c . If the light ray has to travel betwwen two points in space won't the observer on the light ray feel that the light has traveled almost instantly form the source to destination because of the length contraction observed . So how can light's speed be finite when it is almost instantaneous!:confused:

just tried to substitue the muon example with a light ray and got confused can anybody clarify that for me
 
Physics news on Phys.org
You can't have an observer "on the light ray", this isn't allowed in relativity because light always moves (at the speed of light) in every inertial frame. A light ray doesn't have a rest frame, which is the frame an observer "on the light ray" would have to be in. Hence, no such observer can exist.

madhumadanan said:
So how can light's speed be finite when it is almost instantaneous!

You answered your own question! Light is only "almost" instaneous because it moves very fast compared to our everyday experience.

Also, this is the quantum physics forum. If you have more questions about relativity, you should post in the relativity forum https://www.physicsforums.com/forumdisplay.php?f=70 . You will get a better response there.
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Back
Top