MHB Is Matrix A Invertible?

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Matrix A is not invertible because its determinant equals zero, which can be established by transforming it into an upper triangular form that introduces a row of zeros. The discussion emphasizes that if the determinant is zero, the matrix cannot be inverted. Participants highlight the importance of row operations in determining the determinant's value, such as adding or subtracting multiples of rows without changing the determinant. The conversation also references properties of determinants related to elementary row operations. Ultimately, the conclusion is that the matrix's structure leads to a non-invertible status.
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SHow that matrix A is not invertible, where
A = [table="width: 500"]
[tr]
[td]$$cos^2 \alpha$$[/td]
[td]$$sin^2 \beta$$[/td]
[td]$$cos^2 \theta$$[/td]
[/tr]
[tr]
[td]a[/td]
[td]a[/td]
[td]a[/td]
[/tr]
[tr]
[td]$$sin^2 \alpha$$[/td]
[td]$$cos^2 \beta$$[/td]
[td]$$sin^2 \theta$$[/td]
[/tr]
[/table]
 
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Have you considered the Determinant?
 
tkhunny said:
Have you considered the Determinant?

Yes i know if the det = 0 then the matrix is not invertible, or if i can introduce a row or columns of zeros its not invertible.

im not sure but maybe there is something involved with transformations.
 
delgeezee said:
Yes i know if the det = 0 then the matrix is not invertible, or if i can introduce a row or columns of zeros its not invertible.

im not sure but maybe there is something involved with transformations.
Hello delgeezee,
If matrice $$A$$ is invertible Then $$A^T$$ is Also invertible
Regards,
$$|\pi\rangle$$
 
Welcome to MHB, delgeezee! :)

delgeezee said:
Yes i know if the det = 0 then the matrix is not invertible, or if i can introduce a row or columns of zeros its not invertible.

im not sure but maybe there is something involved with transformations.

Yes. It involves transformations that are applicable to determinants.
In particular you can add or subtract a multiple of any row to another row.
The determinant will remain the same under such a transformation.
 
I like Serena said:
Welcome to MHB, delgeezee! :)
Yes. It involves transformations that are applicable to determinants.
In particular you can add or subtract a multiple of any row to another row.
The determinant will remain the same under such a transformation.
Hello,
After I read I like Serena post I realized I missunderstand you did not ask about transport..
I will citate from Ackbach:
"The ERO that takes a multiple of one row, adds it to another row, and stores it in that row, does not change the determinant.

The ERO that switches two rows multiplies the determinant by $-1$.

The ERO that multiplies a row by a nonzero number $m$ also multiplies the determinant by $m$"Regards,
$$|\pi\rangle$$
 
Petrus said:
Hello,
After I read I like Serena post I realized I missunderstand you did not ask about transport..
I will citate from Ackbach:
"The ERO that takes a multiple of one row, adds it to another row, and stores it in that row, does not change the determinant.

The ERO that switches two rows multiplies the determinant by $-1$.

The ERO that multiplies a row by a nonzero number $m$ also multiplies the determinant by $m$"Regards,
$$|\pi\rangle$$
Thank I was able to introduce a row of zeros by reducing the determinant matrices to upper triangular form thus making the determinant = 0 by taking the cofactor expansion along the row of zeros.
 

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