Is My Calculation of Work Along a Defined Curve Correct?

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SUMMARY

The discussion centers on calculating the work (W) along a defined curve (C1) using vector line integrals in the context of electrostatics. The user presents their solution in LaTeX and seeks validation of their calculations, particularly regarding the units of work. A key point of contention arises over the interpretation of the units involved, specifically questioning the dimensional analysis of the final result. The conclusion indicates that while the user believes their units are correct, there is confusion regarding the dimensionality of the denominator in their equation.

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Homework Statement
I would like to confirm whether my solution is correct.
Relevant Equations
vector line integral
I created a problem for myself, which I have documented in LaTeX. I hope it's acceptable that I included snapshots of my pages.

I would like to calculate the Work W along curve C1.
1727268611164.png


I have solved the problem as shown below. Is my solution correct (see Equation 1.11)?
1727268640213.png


The pictures I included are of low quality, so I've attached the main.pdf for your reference.
 

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I am not opening unsolicited pdfs as a matter of principle.

Please note that the forum has LaTeX compatibility. You’ll have to change a couple of delimiters, but displaying equations written in LaTeX generally works quite well.
 
Your final result seems to have the wrong units.
But what's the point of doing this?
 
Hello Nasu, The goal is to improve my understanding by practicing vector line integral problems in physics, specifically those related to electrostatics. Why is the Unit of W not correct? q in [As], Q in [As], e0 in [As]/[Vm] so k in [As]*[Vm] and finally W in [As]*[Vm]/[m]=[VAs]=[Ws]=[Nm]=[J]. So the unit is correct, right?
Thanks and best regards.
 
What is the meaning of "m" in The denominator of your final result? It looks like "k" divided by some quantity in meters. Which does not have dimensions of work.
 

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