Engineering Is My DC Motor Differential Equation Setup Correct?

AI Thread Summary
The discussion focuses on verifying the setup of differential equations for a DC motor to derive its transfer function. Participants emphasize that the transfer function is derived using the Laplace transform, represented as H(s) = output(s)/input(s). Key questions arise regarding the type of input (current or voltage), output (speed or position), and whether factors like armature damping and self-induction should be considered. The model suggests that if armature inductance is ignored, a second-order transfer function can be achieved. The importance of input and output types is highlighted, as they significantly influence the motor's behavior.
Scott77
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question 1.jpg


This question involves finding the transfer function for the system, but I first need to get the differential equations correct. Have I set up the gearbox correctly?

question 1 answer.jpg
 
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Scott77 said:
This question involves finding the transfer function for the system, but I first need to get the differential equations correct.

Well, the transfer function is a differential equation. Using Laplace transform it may be written:

H(s) = output(s)/input(s)

When expressing the transfer function by its Laplace transform, it becomes much easier to calculate at controller.

I have some questions:

- Is it a DC-motor ?
- What is the input: Current or voltage?
- What is the preferred output: Speed or position?
- Is the armature damped ( Da )?
- What about the self induction in the armature, La?

If it's a DC-motor, you should come up with something like this, as for the transfer function:

Image8.gif

Use Masons rule to determine the transfer function as for the motor: ω(s) / Va(s)
 
This is a system modeling question. That diagram and the hints is all the info we got, but we were told to ignore the armature inductance. I don't think it matters what the input type and output type are for this type of question...
 
Of course the input and output type matters. If you change the type of input or output, the motors behaviour will change.

In the model, choosing ω(s) as output, the transfer function will be H(s). Choosing θ(s) as output, the transfer function will be H(s)/s:
θ(s) = ω(s)/s.
 
The input is ea(t) and the output is θL(t) like the question states, that is all I know.
 
Ok, then use these types as input/output.

Setting La = 0, you will get a 2. order transfer function.
 
So is does this look correct?

question 1 answer.jpg
 
Ka and Kb have the same value, but the units are [Nm/A] and [Vs] respectively.

There are people that can prove it.
 

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