It seems to be a key part of the electric and magnetic constants.. Wouldn't this imply that the Planck charge exists somewhere?
#3
KelvinDude
2
0
This is old, but it's kind of sad no one ever answered it, so I'm going to.
No, nothing (known) can have this charge. All known particles have integer multiples of e/3 as their charge (where e is the elementary charge-the magnitude of proton or electron charge). This is not such a multiple.
#4
mquirce
38
0
A layman think that Plank charge is intrinsicaly conected with alpha constant.
Coulomb law show the intaraction of two electric charges in the linear maner: E = e^2 /r.
Here the electric charge is e = 4 08032041 *10^-10 cm^3/2 g^1/2 sec.In this caseobserver is upon one of charges, which in this case are relative static.
Let supose that particles move toward each other in circle with radius r. In this case observer is considered in the centre of circuit. In this case E = e^2 / 2pi *r ecetr. In this case Planc constant is h/2*pi.
Now let supose that charges are moving in traectore in a sphere with radius r. In this case
the trajectore will be 2*pi* alpha. And plank constant must be h / 2*pi*alpha.
So the amount of electric charge is the same. In this case observer is out of sphere.
The Plank charge is e * alpha
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles.
Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated...
Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/
by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
The wavefunction of an atomic orbital like ##p_x##-orbital is generally in the form ##f(\theta)e^{i\phi}## so the probability of the presence of particle is identical at all the directional angles ##\phi##. However, it is dumbbell-shape along the x direction which shows ##\phi##-dependence!