Is showing that a series of functions is differentiable as simple as it appears?

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Homework Help Overview

The discussion revolves around the differentiability of an infinite series of functions, specifically questioning the conditions under which such differentiation can be performed. The subject area is calculus, focusing on series and convergence properties.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the conditions necessary for differentiating an infinite series of functions, questioning the applicability of the Weierstrass M-test and its relation to uniform convergence and differentiability.

Discussion Status

The discussion is active, with participants raising questions about the rules governing the differentiation of series and examining the implications of uniform convergence. There is an ongoing exploration of the relationship between convergence and differentiability.

Contextual Notes

Some participants express uncertainty about the relevance of the Weierstrass M-test to the problem at hand, indicating a potential gap in understanding the connection between uniform convergence and differentiability.

jdinatale
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Here is the problem and my want. I think I might be overlooking something because it seems rather simple...

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"Hence"? how do you know you can differentiate this infinite sum of differentiable functions? what rule tells you that? do you know the weierstrass "M test"?
 
mathwonk said:
"Hence"? how do you know you can differentiate this infinite sum of differentiable functions? what rule tells you that? do you know the weierstrass "M test"?

Yes, I have access to the Weierstrass M-test. But that seems to deal with uniform convergence, and it doesn't quite seem to deal with differentiability or continuity. Unless I'm misunderstanding it.
 
Straight from a book:

"If, on differentiating a convergent infinite series [itex]\sum_{v = 0}^{\infty} G_v(x) = F(x)[/itex] term by term, we obtain a uniformly convergent series of continuous terms [itex]\sum_{v = 0}^{\infty} g_v(x) = f(x)[/itex], then the sum of this last series is equal to the derivative of the sum of the first series"
 

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