Is -t the Correct Integrating Factor for this Diff Eq?

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SUMMARY

The correct integrating factor for the differential equation g' - g/t = t e^t is 1/t, as confirmed by the discussion. The user initially believed the integrating factor to be -t, but upon applying the formula e^∫(-1/t dt), they derived e^(-ln t) = 1/t. This aligns with standard methods for solving first-order linear differential equations, validating the integrating factor as 1/t.

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[SOLVED] Integrating Factor Diff Eqs

Homework Statement



g ' - g/t = t e^t

I'm trying to solve this, but I seem to have run into a problem, according to my book the integrating factor is 1/t, however I believe that it is -t


Homework Equations





The Attempt at a Solution



e^int(-1/t dt) = e^(-lnt) = -t
That is how I found the solution to all the problems requiring an integrating factor before however this situation seems to be different... Do I have the equation in the right form to find the integrating factor?
 
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e^{-\ln t}=e^{\ln t^{-1}}=\frac{1}{t}
 

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