- #1
- 2,076
- 140
Homework Statement
Here is the question from my book along with their solution to the problem :
Part 1 : http://gyazo.com/6467751155edcefec6cc583d164d2ae7
Part 2 : http://gyazo.com/d91752f0a18a72af96f6afc74117f011
Part 3 : http://gyazo.com/7a17dbca3e414d0ddc8458abce2eda9c
Homework Equations
I'll denote the coefficient matrix by the letter A.
I denote my null space operator by N.
t is the transpose of a vector.
The Attempt at a Solution
Now I'm almost positive the book is wrong here. Here's my solution.
Assume that [itex]x = εe^{λt}[/itex] so our equation becomes :
[itex]λεe^{λt} = Aεe^{λt} \Rightarrow (A - λI)ε = 0[/itex]
So we seek eigenvector(s) ε such that the above equation is satisfied. So let's find the eigenvalues for A ( I'll skip some of the boring algebra here ) :
[itex]det(A - λI) = (λ-3)(λ+1)[/itex] Thus λ1 = 3 and λ2 = -1 are eigenvalues for A.
Now to find the eigenvectors for the eigenvalues, we seek the null space of A - λjI. So :
[itex]ε(λ_1) = N(A - 3I) = span\left\{{[1/2 \space \space 1]^t}\right\} [/itex]
[itex]ε(λ_2) = N(A + I) = span\left\{{[-1/2 \space \space 1]^t}\right\} [/itex]
See ^ for some reason I get different eigenvectors than the book does. Everything else that follows after this is exactly the same as the book except my eigenvectors.
Have I made an error somewhere? Or is the book wrong in this case? Some clarification on this would be greatly appreciated.
Thanks in advance.
Last edited: