Is the Change in Internal Energy Just 4513 J When No Work Is Done?

[yinnxz]

Homework Statement

The lid of a pressure cooker forms a nearly
airtight seal. Steam builds up pressure and
increases temperature within the pressure
cooker so that food cooks faster than it does
in an ordinary pot. The system is defined as
the pressure cooker and the water and steam
within it.

If 2.0 g of water is sealed in a pressure
cooker and then vaporized by heating, and
4513 J must be added as heat to completely
vaporize the water, what is the change in the
system’s internal energy?

Relevant Equations

U = Q - W

Since the system is doing no work, would it be just 4513 J? I don't think there is any other information to use

 

[Chestermiller]

Homework Statement: The lid of a pressure cooker forms a nearly
airtight seal. Steam builds up pressure and
increases temperature within the pressure
cooker so that food cooks faster than it does
in an ordinary pot. The system is defined as
the pressure cooker and the water and steam
within it.

If 2.0 g of water is sealed in a pressure
cooker and then vaporized by heating, and
4513 J must be added as heat to completely
vaporize the water, what is the change in the
system’s internal energy?
Relevant Equations: U = Q - W

Since the system is doing no work, would it be just 4513 J? I don't think there is any other information to use

Correct