Is the curl of a vector perpendicular to the vector?

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SUMMARY

The curl of a vector field, specifically in the context of electromagnetic fields, is always perpendicular to the vector field itself. In the discussion, it is established that the relationship (∇×E)·E = -∂B/∂t·E = 0 indicates that the magnetic field (B) and electric field (E) are orthogonal. This conclusion is supported by the properties of the curl operator in vector calculus, which is crucial for understanding the dynamics of electromagnetic fields.

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  • Understanding of vector calculus, particularly the curl operator.
  • Familiarity with electromagnetic theory, specifically Maxwell's equations.
  • Knowledge of the relationship between electric fields (E) and magnetic fields (B).
  • Basic comprehension of time-dependent fields and their interactions.
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Pushoam
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I am asking this because ∇ is also considered as a vector in some cases. Considering it as a vector in this case ,too,
( ∇× E).E = (- ∂ B/∂t).E = - ∂ (B.E)/∂t =0

Since B and E could be arbitrarily dependent on t,
B.E = 0

where B and E are magnetic and electric fields respectively.
This means that B and E are always perpendicular to each other.
 
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