Is the Gas Heated and Cooled Equally in Phase C->D on the Pressure/Volume Graph?

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Homework Help Overview

The discussion revolves around the thermodynamic processes occurring during the transition of a gas from state C to state D on a pressure-volume graph. Participants are examining whether the gas is heated or cooled during this phase and the implications of pressure and volume changes on the gas's temperature and energy state.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the nature of the heating and cooling of the gas, with some suggesting that the gas experiences both heating and cooling equally. Others are exploring the definitions of heating and work in thermodynamic processes, particularly in relation to isothermal and isobaric conditions.

Discussion Status

The discussion is ongoing, with various interpretations of the processes being explored. Some participants are providing insights into the relationship between heat transfer, work done by the gas, and temperature changes, while others are seeking clarification on these concepts.

Contextual Notes

Participants are working with a specific pressure-volume graph and are considering the implications of the ideal gas laws. There is a mention of potential confusion regarding the direction of work done on or by the gas and its effect on temperature.

fawk3s
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[PLAIN]http://img686.imageshack.us/img686/7122/gasgraph.png

It is said that during the phase C->D, the gas is heated. I can see at some points, the pressure*volume is higher than the initial one, which is 10*2=20, but its also lower at some points. So as it starts off as 10*2, and ends as 2*10, I would say that it is both heated and cooled equally. Where am I wrong?

Thanks in advance !
 
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Or is the statement wrong?
 
Being heated means that heat is transferred to the gas or other object, but this does not necessarily mean that the temperature increases. When you make boiled egg, the water is heated but the temperaure of the water remains 100 °C.
The process from B to C looks an isotherm expansion. The gas takes on heat but does work, equal to this heat and the temperature does not change during the process.

ehild
 
B to C actually looks more of an isobaric to me. Since pressure is constant and volume increases, that means the temperature must increase aswell.
And I still can't see how C to D must be heated. The pressure and volume multiplication is the same in both C and D, so I can't really see why the gas would need any outside work done, as in heating it?

Thanks in advance,
fawk3s
 
fawk3s said:
And I still can't see how C to D must be heated. The pressure and volume multiplication is the same in both C and D, so I can't really see why the gas would need any outside work done, as in heating it?


fawk3s
During the process from C to D (it was a mistake writing BC in my previous post) the gas does not need work from the outside world, but does work on it.
PV=constant is characteristic to an isothermal process in case of ideal gases. During such process, the heat gained is equal to the work done by the gas, and the internal energy does not change.

ehild
 
Let me see if I got this straight. In the process from C to D, heat is needed to do work on the outside world. Right?
But a follow up question. If the process was from D to C, the heat or the energy would need to be taken away from the gas in order to do the opposite work, as in cooled?
 
If some outer force does work on the gas, the gas most be cooled in order to keep its temperature constant.

ehild
 
Think I get it. Thanks ehild !
 

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